1.
Scientists are monitoring ground elevation near a volcano to detect signs of potential eruption. The elevation \(h(t)\) , in meters, is measured at regular intervals of time \(t\) , in days.|
\(t\) (days)
|
\(h\) (m)
|
|
0
|
1200.0
|
|
2
|
1200.8
|
|
4
|
1201.7
|
|
6
|
1202.5
|
|
8
|
1203.0
|
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Estimate \(h'(6)\) using a central difference. Be sure to include units on your response.
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Does \(h''(6)\) appear to be positive or negative? Explain.
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What are the units on \(h''(6)\) ? In words, interpret the meaning of the value of \(h''(6)\) .
Answer.
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\(h'(6) \approx \frac{1203.0-1201.7}{8-4} = 0.325\) meters per day
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\(h''(6)\) appears to be negative since the rate of increase of \(h\) seems to be decreasing at \(t=6\) days.
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\(\frac{\frac{meters}{day}}{day}\text{;}\) this is the rate at which the rate of height increase each day, increases









